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Find all the zeros of 3x³+16x²+23x+6 if two of its zeros are -2 and -3 |
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Answer» using PROPERTY, sum of ZEROES = -b/aLet THIRD zero be y-2-3+y = -16/3y = 5-16/3y=-1/3Alter method, if we use, product of zeroes = -d/a(-2)(-3)y = -6/36y = -2y = -1/3 |
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