1.

Find amount and compound interest on 40000 in 3 years at 15/2% per annum​

Answer»

Given :

\bigstar Principle = 40000

\bigstar Time = 3 YEARS

\bigstar rate of INTEREST = 15/2%

\huge{ \mathfrak{solution}}

\green { \boxed{ \red{ \large \: s.i =   \huge \purple{\frac{p \times r \times t}{100} }}}}

\large\implies \: s.i =  \huge \frac{40000 \times 3 \times 15}{100 \times 2}

\large\implies \: 200 \times 3 \times 15

\bigstar \large \boxed{ compound interest = 9000}

\bigstar \red{amount = s.i \:  + \:principle}\bigstar

\implies \: amount = 9000 + 40000

\bigstar \large \boxed{ Amount = 49000}

Mark me as brainliest PLEASE



Discussion

No Comment Found