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Find an approximation of `(0. 99)^5`using the first three terms of its expansion. |
Answer» `0.99 = 1 - 0.01` `:. (0.999)^(5) = (1-0.01)^(5)` `= .^(5)C_(0)(1)^(5) - .^(5)C_(1) (1)^(4) - (-0.01) + .^(5)C_(2)(1)^(3)(0.01)^(2)` (Approximately) ` = 1-5(0.01) + 10(0.01)^(2)` ` = 1-0.05 + 0.001` `= 1.001 - 0.05` `= 0.951` Thus, the value of `(0.99)^(5)` is approximately `0.951`. |
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