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Find an expression for intensity of transmitted light when a polaroid sheet is rotated between I polaroids. In which position of the polaroid sheet will the transmitted intensity be maximum ? |
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Answer» Solution :Hydrogen atom LET r be the radius of the orbit of a hydrogen atom. Forces acting on electron are centrifugal FORCE and electrostatic attraction `(F_(e ))` At equilibrium. `F_(c )=F_(e )` `(mv^(2))/(r )=(1)/(4PI epsilon_(0))(e^(2))/(r^(2))` According to Bohr’s postulate `mvr = (nh)/(2pi)rArr u=(nh)/(2pi mr)` `m((nh)/(2pi mr))^(2)(1)/(r )=(1)/(4pi epsilon_(0))(e^(2))/(r^(2))rArr (mn^(2)h^(2))/(4pi^(2)m^(2)r^(2)r)=(1)/(4pi epsilon_(0))(e^(2))/(r^(2))` `r=(m^(2)h^(2)epsilon_(0))/(pi me^(2))rArr therefore r ALPHA n^(2)` |
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