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    				| 1. | Find angle ‘θ’ between the vectors a = i + j - k and vector b = i - j + k | 
| Answer» The angle θ between two vectors a and vector b is given by cosθ = (vector a x vector b)/(|vector a||vector b|) Now, vector(a.b) = (i + j - k) x (i - j + k) = 1 - 1 - 1 = - 1 Therefore, we have cosθ = -1/3 ⇒ θ = cos-1(-1/3) | |