Find AP whose 3rd term is 16 and 7th term is more than the 5th term by

1.	Find AP whose 3rd term is 16 and 7th term is more than the 5th term by 12
Answer» Answer: a = 4 Step-by-step explanation: Let a be the First term, a3 be the third term, a5 be the 5th term and a7 be the 7TH term a3 = 16 a7 = a5 + 12 ............ (1) Let the common difference be "d" Common difference is equal in AP So, a7 = a5 + d + d = a5 + 2d ............(2) From Equation (1) & (2) a5 + 12 = a5 + 2d 2d = 12 d = 6 From Given, we get that a3 = 16 a3 = a + 2d = 16 a + ( 2 × 6 ) = 16 [ We know that d = 6 ] a + 12 = 16 a = 4 So first term is 4 .... We can find AP by adding d continuously So, AP is 4, 10, 16, 22, 28....... Hope it helps !!!

Find AP whose 3rd term is 16 and 7th term is more than the 5th term by 12

Answer»

Answer:

a = 4

Step-by-step explanation:

Let a be the First term, a3 be the third term, a5 be the 5th term and a7 be the 7TH term

a3 = 16

a7 = a5 + 12 ............ (1)

Let the common difference be "d"

Common difference is equal in AP

So,

a7 = a5 + d + d = a5 + 2d ............(2)

From Equation (1) & (2)

a5 + 12 = a5 + 2d

2d = 12

d = 6

From Given, we get that

a3 = 16

a3 = a + 2d = 16

a + ( 2 × 6 ) = 16 [ We know that d = 6 ]

a + 12 = 16

a = 4

So first term is 4 .... We can find AP by adding d continuously

So, AP is 4, 10, 16, 22, 28.......

Hope it helps !!!