1.

Find at least 3 solutions from each of the following linear equations in two variables 6x - 3y = 12 ii) 3x + 2y + 6 = 0​

Answer»

Step-by-step explanation:3x+2y=5 ----------(1) 6x+3y=12 ----------(2) MULTIPLYING equation 1 by 2, we GET 6x+4y=10 ---------(3) now, SUBTRACT equation 3 rd from 2 nd equation (6x+3y=12) - (6x+4y=10) (6x+3y=12) - (6x-4y= -10) 6x-6x+3y-4y = 12-10 -y = 2 y = -2 put VALUE y = - 2 in equation e rd ,we get 6x+4×-2=10 6x-8=10 6x= 10 +8 6x= 18 x =18/6 x = 3 (x,y)=( 3, -2)



Discussion

No Comment Found