InterviewSolution
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InterviewSolution
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Find bond enthalpy of S-S bond from the following data: `C_(2)H_(5)-S-C_(2)H_(5)," "DeltaH_(f)^(@)=-147.2kJ" "mol^(-1)` `C_(2)H_(5)-S-S-C_(2)H_(5)," "DeltaH_(f)^(@)=-201.9kJ" "mol^(-1)` `S(g)," "DeltaH_(f)^(@)=222.8kJ" "mol^(-1)` |
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Answer» `4C(s)+5H_(2)O+StoH-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-S-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-H` `4C(s)+5H_(2)+2StoH-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-S-S-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-H` `DeltaH=sum(BE)_(R)-sum(BE)_(P)` (i). `-147.2="Heat of atomization of 4C, 10H, 1S"` `-BE" of "10(C-H),2(C-s),2(C-C)` (ii) `-201.9="Heat of atomization of 4C",10H,2S` `-BE` of `10(C-H),2(C-S),2(C-C),(S-S)` Subtracting (i) from (ii), `-201.9+147.2="Heat of atomization of "1S-BE" of "(S-S)` `=222.8kJ-BE` of `(S-S)` BE of `(S-S)=277.5kJ` |
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