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| 1. | Find constant of variation and write equation of variation for every example given below:i. p ∝ (1/q); if p = 15 then q = 4.ii. z ∝ (1/w); when z = 2.5 then w = 24iii. s ∝ (1/t2); if s = 4 then t = 5.iv. x ∝ (1/√y); if x = 15 then y = 9. | 
| Answer» i. p ∝ (1/q) … [Given] ∴ p = k × (1/q) where, k is the constant of variation. ∴ p × q = k …(i) When p = 15, q = 4 ∴ Substituting p = 15 and q = 4 in (i), we get p × q = k ∴ 15 × 4 = k ∴ k = 60 Substituting k = 60 in (i), we get p × q = k ∴ p × q = 60 This is the equation of variation. ∴ The constant of variation is 60 and the equation of variation is pq = 60. ii. z ∝ (1/w) …[Given] ∴ z = k × (1/w) where, k is the constant of variation, ∴ z × w = k …(i) When z = 2.5, w = 24 ∴ Substituting z = 2.5 and w = 24 in (i), we get z × w = k ∴ 2.5 × 24 = k ∴ k = 60 Substituting k = 60 in (i), we get z × w = k ∴ z × w = 60 This is the equation of variation. ∴ The constant of variation is 60 and the equation of variation is zw = 60. iii. s ∝ (1/t2) …[Given] ∴ s = k x (1/t2) ∴ where, k is the constant of variation, ∴ s × t2 = k …(i) When s = 4, t = 5 ∴ Substituting, s = 4 and t = 5 in (i), we get s × t2 = k ∴ 4 × (5)2 = k ∴ k = 4 × 25 ∴ k = 100 Substituting k = 100 in (i), we get s × t2 = k ∴ s × t2 = 100 This is the equation of variation. ∴ The constant of variation is 100 and the equation of variation is st2 = 100. iv. x ∝ (1/√y) …[Given] ∴ x = k x (1/√y) where, k is the constant of variation, ∴ x × √y = k …(i) When x = 15, y = 9 ∴ Substituting x = 15 and y = 9 in (i), we get x × √y = k ∴ 15 × √9 = k ∴ k = 15 × 3 ∴ k = 45 Substituting k = 45 in (i), we get x × √y = k ∴ x × √y = 45. This is the equation of variation. ∴ The constant of variation is k = 45 and the equation of variation is x√y = 45. | |