The total remuneration paid to laborers, employed to harvest soybean i

1.	The total remuneration paid to laborers, employed to harvest soybean is in direct variation with the number of laborers. If remuneration of 4 laborers is Rs 1000, find the remuneration of 17 laborers.
Answer» Let, m represent total remuneration paid to laborers and n represent number of laborers employed to harvest soybean. Since, the total remuneration paid to laborers, is in direct variation with the number of laborers. ∴ m ∝ n ∴ m = kn …(i) where, k = constant of variation Remuneration of 4 laborers is Rs 1000. i. e., when n = 4, m = Rs 1000 ∴ Substituting, n = 4 and m = 1000 in (i), we get m = kn ∴ 1000 = k × 4 ∴ k = 1000/4 ∴ k = 250 Substituting, k = 250 in (i), we get m = kn ∴ m = 250 n …(ii) This is the equation of variation Now, we have to find remuneration of 17 laborers. i. e., when n = 17, m = ? ∴ Substituting n = 17 in (ii), we get m = 250 n ∴ m = 250 × 17 ∴ m = 4250 ∴ The remuneration of 17 laborers is Rs 4250.

The total remuneration paid to laborers, employed to harvest soybean is in direct variation with the number of laborers. If remuneration of 4 laborers is Rs 1000, find the remuneration of 17 laborers.

Answer»

Let, m represent total remuneration paid to laborers and n represent number of laborers employed to harvest soybean.

Since, the total remuneration paid to laborers, is in direct variation with the number of laborers.

∴ m ∝ n

∴ m = kn …(i)

where, k = constant of variation

Remuneration of 4 laborers is Rs 1000.

i. e., when n = 4, m = Rs 1000

∴ Substituting, n = 4 and m = 1000 in (i), we get m = kn

∴ 1000 = k × 4

∴ k = 1000/4

∴ k = 250 Substituting, k = 250 in (i), we get m = kn

∴ m = 250 n …(ii)

This is the equation of variation

Now, we have to find remuneration of 17 laborers.

i. e., when n = 17, m = ?

∴ Substituting n = 17 in (ii), we get m = 250 n

∴ m = 250 × 17

∴ m = 4250

∴ The remuneration of 17 laborers is Rs 4250.