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Find ` (dy)/(dx) , " if x " = 2 cos theta - cos 2 theta ` and y = 2sin theta - sin 2 theta `.A. `tan""(3 theta )/(2)`B. `- tan""(3 theta )/(2)`C. `cot""(3 theta )/(2)`D. `-cot""(3 theta)/(2)` |
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Answer» Correct Answer - A Given `x=2 cos theta - cos 2 theta ` and `y= 2 sin theta- sin 2 theta ` `(dy)/(d theta )=- 2 sin theta + 2 sin 2 theta ` and `(dy)/(d theta)=(2 cos theta - 2 cos 2 theta )/(-2 sin theta + 2 sin 2 theta )` `=( cos theta - cos 2 theata )/( sin 2 theta - sin theta )` `=( 2 sin""((theta+ 2 theta )/(2)) sin ""((2 theta - theta)/( 2)))/( 2 cos ""((theta+ 2cos theta )/(2)) sin""((2 theta -theta )/(2)))` `=tan""(3 theta )/(2)` |
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