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Find dy/dx where y=(ax^3+3)^4Sol: Let t=ax^3+3dy/dx=dt^4/dt×dt/dxdy/dx=4t^3 × 3x^2 ady/dx=4(ax^3+3) × 3x^2 aexplain the third step why we wrote 4(ax^3+3) and not 4(ax^3+3)^3

Answer» Find dy/dx where y=(ax^3+3)^4

Sol: Let t=ax^3+3
dy/dx=dt^4/dt×dt/dx
dy/dx=4t^3 × 3x^2 a
dy/dx=4(ax^3+3) × 3x^2 a


explain the third step why we wrote 4(ax^3+3) and not 4(ax^3+3)^3


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