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Find dy/dx where y=(ax^3+3)^4Sol: Let t=ax^3+3dy/dx=dt^4/dt×dt/dxdy/dx=4t^3 × 3x^2 ady/dx=4(ax^3+3) × 3x^2 aexplain the third step why we wrote 4(ax^3+3) and not 4(ax^3+3)^3 |
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Answer» Find dy/dx where y=(ax^3+3)^4 Sol: Let t=ax^3+3 dy/dx=dt^4/dt×dt/dx dy/dx=4t^3 × 3x^2 a dy/dx=4(ax^3+3) × 3x^2 a explain the third step why we wrote 4(ax^3+3) and not 4(ax^3+3)^3 |
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