Find equation of the line perpendicular to the line `x" "" "7y" "+" "5" "=" "0`and having x intercept 3.

Find equation of the line perpendicular to the line `x" "" "7y" "+" "5

1.	Find equation of the line perpendicular to the line `x" "" "7y" "+" "5" "=" "0`and having x intercept 3.
Answer» `x-7y+5=0 Rightarrow y=(1)/(7)x+(5)/(7)` `therefore` slope of the given line=`(1)/(7)` `therefore` slope of a line perpendicular to the given line=`-7[therefore m_(2)=(-1)/(m_(1))]` Thus, m=-7 and d=3, where d=x, intercept. Now, the equation of a line with slope -7 and x-intercept 3 is given by `y=-7(x-3)" "[therefore y=m(x-d)]` `Rightarrow 7x+y-21=0`, where is the required equations.

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Find equation of the line perpendicular to the line `x" "" "7y" "+" "5" "=" "0`and having x intercept 3.

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