Saved Bookmarks
| 1. |
Find equivalent resistance of the network in Fig. between points (i) A and B and (ii) and C. |
|
Answer» Solution :(i) The `100 OMEGA` and `30Omega` resistors are connected in parallel between POINTS A and B. The EQUIVALENT resistance between A and B is `R_(1)=(10xx30)/(10+30)" OHM "=7.5Omega` (ii) The resistance `R_(1)` is connected in series with resistor of `7.5Omega`, hence the equivalent resistance between points A and B is C is, `R_(2)=(R_(1)+7.5)" ohm "=(7.5+7.5)" ohm "=15Omega.` |
|