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Find fog (2) and gof (1) when f: R → R; f(x) = x2 + 8 and g: R → R; g(x) = 3x3 + 1. |
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Answer» Given as f: R → R; f(x) = x2 + 8 and g: R → R; g(x) = 3x3 + 1. Consider that (fog)(2) = f(g(2)) = f(3 × 23 + 1) = f(3 × 8 + 1) = f(25) = 252 + 8 = 633 (gof)(1) = g(f(1)) = g(12 + 8) = g(9) = 3 × 93 + 1 = 2188 |
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