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Find gof and fog when f: R → R and g: R → R is defined by f(x) = 2x + x2 and g(x) = x3 |
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Answer» Since, f:R → R and g:R → R fog:R → R and gof:R → R f(x) = 2x + x2 and g(x)=x3 Now, gof(x) = g(f (x)) =g(2x + x2) gof (x)=(2x + x2)3 = x6 + 8x3 + 6x5 + 12x4 and fog(x)=f(g(x))= f(x3) ⇒ fog(x) = 2x3 + x6 So, gof(x) = x6 + 6x5 + 12x4 + 8x3 and fog(x) = 2x3 + x6 |
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