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Find heat loss in the above circuitDelta H = Energy [initially -finally ]on capacitor |
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Answer» SOLUTION :` = [{(1)/(2) XX 5XX ( 20) ^(2) +(1)/(2) xx 2xx (5)^(2) }-` ` {(1)/(2) xx ( (525)/( 6))^(2) xx(1)/(5) +(1)/(2) ((75)/( 6))^(2) xx(1)/(2) +(1)/(2) ((135)/( 6))^(2) xx (1)/(2) }]xx10 ^(-6) J` |
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