1.

Find `lambda,`when the projection of ` vec a=lambda hat i+ hat j+4 hat k on vec b=2 hat i+6 hat j+3 hat k i s 4 `units.

Answer» Correct Answer - `lambda=5`
Clearly, `(vec(a).vec(b))/(|vec(b)|)=4rArr ((2lambda+6+12))/(sqrt(4+36+9))=4rArr (2lambda+18)=28 rArr 2lambda=10 rArr lambda=5`.


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