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    				| 1. | If `vec(a)` and `vec(B)` are two vectors such that `|vec(a)|=|vec(b)|=sqrt(2)` and `vec(a).vec(b)=-1`, find the angle between `vec(a)` and `vec(b)`.A. `(pi)/(6)`B. `(pi)/(4)`C. `(pi)/(3)`D. `(2pi)/(3)` | 
| Answer» Correct Answer - D `cos theta= (vec(a).vec(b))/(|vec(a)||vec(b)|)=(-1)/(sqrt(2)xxsqrt(2))=(-1)/(2)rArrtheta=(2pi)/(3)`. | |