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Find modulus and argument of (1-√3i) |
Answer» AnswerMODULUS is 4 ARGUMENT is 60° Step-by-step explanation:Modulus of complex number x + iy is \SQRT{ {x}^{2} + {y}^{2} } x 2 +y 2
Modulus of given complex number is \sqrt{ {1}^{2} + { \sqrt{3} }^{2} } 1 2 + 3
2
\sqrt{1 + 3} 1+3
\sqrt{4} 4
22 Now argument of a complex number is tan^{ - 1} \frac{y}{x}tan −1
x y
tan^{ - 1} \frac{ \sqrt{3} }{1}tan −1
1 3
tan^{ - 1} \sqrt{3}tan −1
3
\frac{\pi}{3} 3 π
=> 60° |
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