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| 1. |
Find `.^(n)C_(3)`, if `.^(n)C_(7)=.^(n)C_(4)`. |
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Answer» `.^(n)C_(7)=.^(n)C_(4)rArrn=7+4=11` So `.^(n)C_(3)=.^(11)C_(3)=(11xx10xx9)/(1xx2xx3)=165`. |
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