1.

Find our the entropy change in surroudings when 1 mole of H_(2)O(l) is formed under standard conditions Delta_(f)H^(ө)=-286" kJ "mol^(-1)

Answer»

959.7 `JK^(-1)mol^(-1)`
286 `JK^(-1)mol^(-1)`
`-959.7" "JK^(-1)" "mol^(-1)`
`-286JK^(-1)mol^(-1)`

Solution :`H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l),Delta_(f)H^(@)=-286" kJ "mol^(-1)`
When 1 mole of heat is absorbed by the surrounding, i.e.,
`q_("surr")=+286" kJ "mol^(-1)`
`DELTAS=(q_("surr"))/(T)=(286 " kJ "mol^(-1))/(298K)=959.7JK^(-1)mol^(-1)`.


Discussion

No Comment Found