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Find out `InK_(eq)` for the formation of `NO_(2)` from `NO` and `O_(2)` at `298 K` `NO_(g)+(1)/(2)O_(2)hArrNO_(2)g` Given: `DeltaG_(f)^(@)(NO_(2))=52.0KJ//mol e` `Delta_(f)^(@)(NO)=87.0KJ//mol e` `Delta_(f)^(@)(O_(2))=0KJ//mol e`A. `(35xx10^(3))/(8.314xx298)`B. `-(35xx10^(3))/(8.314xx298)`C. `(35xx10^(3))/(2.303xx8.314xx298)`D. `(35xx10^(3))/(2xx298)` |
Answer» Correct Answer - A `NO+(1)/(2)O_(2)hArrNO_(2)` `DeltaG_(RxH)^(@)=52-87=-35KJ` `DeltaG^(@)=-RTInK_(eq)` `InK_(eq)=(35000)/(8.314xx298).` |
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