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Find out normality of the solution prepasred by dissolving 9.8 gram H_(2)SO_(4) to 500 mL solution ? |
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Answer» `4.0` W = 9.8 gram M = 98 gram/mole `E=("49 gram")/("eq. WT.")` Normality `(N)=(1000xx W)/(E xx V)` `= (1000xx9.8)/(49xx500)=0.4 N` |
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