Saved Bookmarks
| 1. |
Find out the amount of the work done to separate the charges at infinite distance . |
|
Answer» Solution :Potential ENERGY of charge system. `U = (1)/(4 pi in_(0)) [ (q_(A) q_(B))/(AB) + (q_(A) q_(B))/(AC) + (q_(B) q_(C))/(BC)] = (1)/(4 pi in_(0)) [ (q(-4q))/(l) + (q(2Q))/(l) + ((-4q) (2q))/(l)]` `= - (1)/(4 pi in_(0)) * (10 q^(2))/(l)` `therefore` Work done to separate the CHARGES at infinite distance ` W = U_(oo) + U = + (1)/(4 pi in_(0)) * (10 q^(2))/(l)` |
|