Saved Bookmarks
| 1. |
Find out the amount of the work done to separate the charges at infinite distance. |
|
Answer» Solution :Net P.E. of the SYSTEM `= (1)/( 4pi in _0) (q^(2) )/( L) [-4+2-8]` ` = ( (-10 )q^(2))/( 4pi in _0 l) ` ` therefore ` Work DONE `( 10 q^(2))/( 4pi in _0l ) = ( 5q^(2)) /( 2pi in _0l ) ` |
|