Saved Bookmarks
| 1. |
Find out the atomic number of the element which gives X-ray of minimum wavelength 0.252 nm of K series (R=1.09737xx10^(7)m^(-1)) |
|
Answer» 2 For the minimum wavelength we have to take `n=oo` `:. (1)/(lambda_(min))=R(Z-1)^(2)[1-0]` `:.(1)/(lambda_(min))=R(Z-1)^(2)` `:.[Z-1]^(2)=(1)/(R lambda_(min))=(1)/(1.097xx10^(7)xx252xx10^(-12))` `:.[Z-1]^(2)=(10^(5))/(1.097xx252)=0.0036174xx10^(5)` `:.[Z-1]^(2)=361.74` `Z-1=19.02=19` `:.Z=19+1=20` |
|