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Find out the difference of wave number between second and first spectral lines of Lyman series of hydrogen atom's spectrum. R=10.9xx10^(7)m^(-1) |
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Answer» Solution :For SECOND line of Lyman series of hydrogen atom and for first line of Lyman series `(1)/(lambda_(2))=R[(1)/(1^(2))-(1)/(3^(2))]=R[(1)/(1)-(1)/(9)]` `(1)/(lambda_(2))=(8R)/(9) ....(1)` and for first line of Lyman series, `(1)/(lambda_(1))=R[(1)/(1^(2))-(1)/(2^(2))]=R[(1)/(1)-(1)/(4)]` `(1)/(lambda_(1))=(3R)/(4)".....(2)` `rArr`Different of wave number. `(1)/(lambda_(2))-(1)/(lambda_(1))=(8R)/(9)-(3R)/(4)=R[(8)/(9)-(3)/(4)]` `=1.09xx10^(7)[(32-27)/(36)]` `=1.09xx10^(7)xx(5)/(36)` |
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