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Find out the following a. `V_A - V_B` b. `V_B - V_C` c. `V_C - V_A` d. `V_D - V_C` e. `V_A - V_D` f. Arrange the order of potential for points (A, B,C and D). . |
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Answer» (i) The potential difference between two points in electric field is `|Delta V_(AB)| = - vec E . vec(AB) = E d cos theta = E. d` =`E d = 20 xx 2 xx 10^(-2) = 0.4` So `V_A - V_B = 0.4 V` Negative because in the direction of electric field, potential always decreases. (ii) `|Delta V_(BC) | = E d = 20 xx 2 xx 10^(-2) = 0.4` d is the distance between the equipotential passing through B and C, so `V_B - V_C = 0.4 V` (iii) `|Delta V_(CA) | = E d = 20 xx 4 xx 10^(-2) = 0.8` So `V_C - V_A = -0.8 V` Negative because in the direction of electric field, potential always decreases. (iv) `|Delta V_(DC) | = E d = 20 xx 0 = 0` So `V_D - V_C = 0` Because the effective distance between D and C is zero. Also potential difference between C and D is zero as both the points lie on same equipotential. (v) `|Delta V_(A D)| = Ed = 20 xx 4 xx 10^(-2) = 0.8` Here d is the distance between equipotential pasing through A and D. So `V_A - V_D = 0.8 V` Because in the direction of electric field, potential always decreases. (vi) The order of potential is `V_A gt V_B gt V_C = V_D`. |
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