1.

Find out the most stable ion in its reduced form.

Answer»

`Cl^(-)`
`Cr^(3+)`
`Cr`
`Mn^(2+)`

SOLUTION :`E_(red)^(@)` is highest for `MnO_(4)^(-)//Mn^(2+)`. This shows that this reduction takes place most easiliy. Hence, `Mn^(2+)` will be most stable ion in the reduced FORM.


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