find out the standard free energy change at `60^(@)C`and at 1 atn if the `N_(2)O_(4)` is 50 % dissociatedA. `-800 .0 kJ mol^(-1)`B. `+ 800.0 kJ mol^(-1)`C. `789.89 JK^(-1) mol^(-1)`D. `+ 789.98 JK^(-1)mol ^(-1)`

find out the standard free energy change at `60^(@)C`and at 1 atn if t

1.	find out the standard free energy change at `60^(@)C`and at 1 atn if the `N_(2)O_(4)` is 50 % dissociatedA. `-800 .0 kJ mol^(-1)`B. `+ 800.0 kJ mol^(-1)`C. `789.89 JK^(-1) mol^(-1)`D. `+ 789.98 JK^(-1)mol ^(-1)`
Answer» Correct Answer - c `N_(2)O_(4)(g)Leftrightarrow2NO_(2)(g)` ` N_(2)O_(4)` is 50 % dissociated , the mole fraction of the substance is given by `x_(n2O4)= (1-05)/(1 + 0.5), x_(no2)= (2xx0.5)/(1+0.5)` `P_(n2O4)=0.5/1.5xx 1 atm , p_(no2)1/1.5 xx 1atm` the equilibrium constant ` K_(p)` is given by `k_(p) =(P_(no_(2)))^(2)/(P_(N_(2)O_(4)))=1.5/((1.5)^(2)(0.5))=1/0.75=1.33` ` Delta_(a)G^(Theta)=-RT in K_(p)` `=- 8.314 Jk^(-1)mol^(-1)xx333 K xx 2.303xx 0.1239` `=-789.89 JK^(-1) mol^(-1)`

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find out the standard free energy change at `60^(@)C`and at 1 atn if the `N_(2)O_(4)` is 50 % dissociatedA. `-800 .0 kJ mol^(-1)`B. `+ 800.0 kJ mol^(-1)`C. `789.89 JK^(-1) mol^(-1)`D. `+ 789.98 JK^(-1)mol ^(-1)`

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