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Find potential difference between points A and B of the network shown in Fig. and distribution of given main current through different resistors. |
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Answer» Solution :Between points A and B RESISTORS of `4OMEGA, 6OMEGA and 8Omega` RESISTANCE are in series and these in PARALLEL to `9Omega` resistor. Equivalent resistance of series combination is `R_(1)=(4+6+8)" ohm "=18` If equivalent resistance between A and B is `R=9xx18//(9+18)" ohm"=6Omega` Potential difference between A and B is `V=IR=2.7xx6V=16.2V` Current through `9Omega` resistor `=16.2//9=1/8A` Current through `4Omega, 6Omega and 8Omega` resistor `=2.7-1.8=0.9A`. |
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