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Find R–1 , when (i) R = {(1, 2), (1, 3), (2, 3), (3, 2), (4, 5)} (ii) R = {(x, y) : x, y ϵ N, x + 2y = 8}. |
Answer» (i) R = {(1, 2), (1, 3), (2, 3), (3, 2), (4, 5)} R–1 = {(2, 1), (3, 1), (3, 2), (2, 3), (5, 4)} (ii) R = {(x, y) : x, y ϵ N, x + 2y = 8}. y = \(\frac{8-x}{2}\) Put x = 2, y = 3 Put x = 4, y = 2 Put x = 6, y = 1 R = {(2, 3), (4, 2), (6, 1)} R–1 = {(3, 2), (2, 4), (1, 6)} |
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