1.

Find radius of electron in first orbit when hydrogen atom in ground state is excited by mean of light of =975Å

Answer»

`1.1 xx 10^(-11)m`
`2.5 xx 10^(-10)m`
`3.2 xx 10^(-9)m`
`6.6 xx 10^(-8)m`

Solution :`R=r_(0).n^(2)/Z," where r"_(0)=(epsi_(0) h^(2))/(e^(2)PIM)`
`rArr r_(0)=5.3 xx 10^(-11) m`
`r=5.3 xx 10^(-11) xx 1^(2)/5=1.1 xx 10^(-11) m`


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