Find: `sin^(-1)(sin (2pi)/(3))`

1.	Find: `sin^(-1)(sin (2pi)/(3))`
Answer» `sin(sin""(2pi)/(3))=sin^(-1)[sin(pi-(pi)/(3))] " " { :. " Range of " sin^(-1)x=[-(pi)/(2),(pi)/(2)]}` `sin^(-1)(sin""(pi)/(3))=(pi)/(3)`

Discussion

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If `sin(sin^(-1)1/5+cos^(-1)x)=1,`then find the value of `xdot`
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`tan^(-1)sqrt(3)-cot^(-1)(-sqrt(3))`is equal to(A) `pi` (B) `-pi/2` (C) 0 (D) `2sqrt(3)`A. `pi`B. `-(pi)/(2)`C. `0`D. `2sqrt(3)`
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Find the value of: `tan1/2[sin^(-1)(2x)/(1+x^2)+cos^(-1)(1-y^2)/(1+y^2)],|x|0`and `x y" "