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Find the 31st term of an AP whose 11th term is 38 and the 16th term​

Answer»

178Step-by-step explanation:Given that, a11​=38   a16​=73 We KNOW that,an​=a+(n−1)da11​=a+(11−1)d38=a+10d ... (i)Similarly,a16​=a+(16−1)d73=a+15d ... (II)On subtracting (i) from (ii), we get35=5d∴d=7From equation (i),38=a+(10)(7)⇒38−70=a∴a=−32Now a31​=a+(31−1)d=−32+30(7)=−32+210=178Hence, 31ST  term is 178



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