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Find the 50th term of the series `2+3+6+11+18+…`.A. `49^(2)-1`B. `49^(2)`C. `50^(2)+1`D. `49^(2)+2` |
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Answer» Correct Answer - D Let `T_(n)" be the "n^(th)` term of the given series. We observe that the successive differences of the terms form an A.P. So, let its `n^(th)` term be given by `T_(n)=an^(2)+bn+c` Putting n=1,2,3, we get a+b+c=2,4a+2b+c=3 and, 9a+3b+c=6 Solving these equations, we get a=1, b=-2, c=3 `:." "T_(n)=n^(2)-2n+3=(n-1)^(2)+2` `rArr" "T_(50)=49^(2)+2` D is the answer of this question
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