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Find the 6th term and the nth term of the sequence 3/2,3/4,3/8... |
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Answer» A.P = 3/2, 3/4 , 3/8 d = 3/4 - 3/2 = - 3/4 a = 3/2 6th term = a + 5D = 3/2 + 5 × -3/4 = 3/2 - 15/4 = 6 - 15 / 4 = -9/4 nth term = a + (n-1)d => an = 3/2 -3/4 n + 3/4 => an = 3/2 + 3/4 - 3/4n => an = 9/4 - 3/4n => an = 3/4 ( 3 - n ) |
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