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Find the (a)Maximm frequency,and (b)Minimum wavelength of X-rays produced by 30 kV electrons. |
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Answer» Solution :Here V=30 KV=`3XX10^(4)` V,H=`6.63xx10^(-34)` Js (a) [maximum K.E of photon of X-ray]=[Maximum K.E. of electron accelerated with volt V] `therefore hv_(max)=eV` `therefore v_(max)=(eV)/(h)` `=(1.6xx10^(-19)xx3xx10^(4))/(6.63xx10^(-34))` `0.72398xx10^(19)Hz` `therefore v_(max)7.24xx10^(18)Hz` (b) Now, `C=V_(max)xxlambda_(min)` `therefore lambda_(min)=(c)/(v_(max))` `=(3xx10^(8))/(7.24xx10^(18))` `=0.41436xx10^(-10)m=0.0414` NM |
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