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Find the (a) maximum frequency, and (b) minimum wavelength of X-rays produced by 30kV electrons. |
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Answer» Solution :Here the accelerating voltage `V=30kV=30xx10^(3)V` (a) MAXIMUM frequency of X-rays produced `v_(MAX)=(E)/(H)=(eV)/(h)=(1.6xx10^(-19)xx30xx10^(3)J)/(6.63xx10^(-34)J)=7.24xx10^(18)Hz` (b) The minimum wavelength of X-rays produced `lamda_("min")=(c)/(v_(max))=(3XX10^(8))/(7.24xx10^(18))=4.1xx10^(-11)m=0.041nm`. |
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