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Find the acceptance angle of a material which has a numerical aperture of 0.707 in air.(a) 30(b) 60(c) 45(d) 90I got this question in class test.This question is from Refractive Index and Numerical Aperture in division EM Wave Propagation of Electromagnetic Theory

Answer»

The correct option is (c) 45

Easy explanation: The numerical APERTURE is GIVEN by NA = n SIN θa, where n is the refractive index. It is unity in air. Thus NA = sin θa. To GET θ= sin^-1(NA), put NA = 0.707, thus θa = sin^-1(0.707) = 45 degree.



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