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    				| 1. | Find the amount at the end of 12 years of an annuity of Rs 5,000 payable at the beginning of each year, if the money is compounded at 10% per annum. | 
| Answer» Here a = 5000, i = 10% = \(\frac{10}{100}\) = 0.1, n = 12 Amount A = (1 + i) \(\frac{a}{i}\)[(1 + i)n – 1] = (1 + 0.1) \(\frac{5000}{\frac{10}{100}}\)[(1 + 0.1)12 – 1] = (1.1) 50000 [(1.1)12 – 1] = 55000 [3.1384 – 1] = 55000 [2.1384] = Rs 1,17,612 | |