Find the angle between the large hand and small hand of a clock at the

1.	Find the angle between the large hand and small hand of a clock at the time `4:30`.
Answer» For small hand Angle subtends in 12 hours `=360^(@)` 4 hrs 30 min = 4 hrs + `30/60` hrs `=9/2` hrs Angle subtends in `9/2` hours `=9/2 xx 360^(@)/12=135^(@)` For large hand 1 hour = angle subtends in 60 min. = `360^(@)` `rArr` Angle subtends in 30 min. =`180^(@)` `therefore` Angle between large hand and small hand at the time `4:30` `=180^(@)- 135^(@)=45^(@)`.

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