1.

Find the angle between two vectors `hatA=2hati+hatj-hatk` and `hatB=hati-hatk`

Answer» `cos theta=(vecA,vecB)/(|vecA||vecB|)=(2+0+1)/(sqrt(6)sqrt(2))=(1)/(2sqrt(2))sqrt(3)/(2)rArrtheta=30^(@)`


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