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Find the angle made by the line `x+sqrt3y-6=0` with the positive direction of the x-axis. |
Answer» Let the required angle be `theta`. `"Now", x+sqrt3y-6=0 Rightarrow y=-(1)/(sqrt3)x+(6)/(sqrt3)` `therefore m=-(1)/(sqrt3) Leftrightarrow tan theta =-(1)/(sqrt3)=-tan 30^(@)=tan(180^(@)-30^(@))=tan 150^(@)` `therefore theta=150^(@)` Hence, the given line makes an angle of `150^(@)` with the positive direction of the x-axis. |
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