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Find the angular momentum of an oxygen molecule whose rational energy is E=2.16 meV and the distance between the nuclei is d=121p m. |
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Answer» Solution :The angular momentum is `SQRT(2E)=M` Now `I=(md^(2))/(4) (m = "mass of" O_(2) "molecule")=1.9584xx10^(-39) GMC^(2)` So `M= 3.68xx10^(-27) ERG sec.=3.49 ħ` (This corresponding to `J=3)` |
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