1.

Find the angular momentum of an oxygen molecule whose rational energy is E=2.16 meV and the distance between the nuclei is d=121p m.

Answer»

Solution :The angular momentum is `SQRT(2E)=M`
Now `I=(md^(2))/(4) (m = "mass of" O_(2) "molecule")=1.9584xx10^(-39) GMC^(2)`
So `M= 3.68xx10^(-27) ERG sec.=3.49 ħ`
(This corresponding to `J=3)`


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