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Find the apparent depth and apparent shift of an object placed at the bottom of the vessel containing a glass slap of thickness 10 cm and water of height 50 cm. as shown in the figure. |
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Answer» Solution :Apparent DEPTH = `50/n_(W) + 10/n_(g) = 50/(4//3) + 10/(3//2) = (75/2 + 20/3) cm = 44.17 cm` `therefore` Apparent SHIFT = (50+ 10 - 44.17) cm = 15.83 cm. |
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