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    				| 1. | Find the are of an equilateral triangle having each side of length 10 cm . `["Take"sqrt(3)=1.732.]` | 
| Answer» Here ,a = 10 cm `"(i) Area of the triangle"=((sqrt(3))/(4)xxa^(2))sq " units"` `=((sqrt(3))/(4)xx10xx10)cm ^(2)= (25xxsqrt(3))cm^(2)` `= (25xx1.732) cm ^(2)= 43.3 cm ^(2) ` (ii) Height of the triangle `=((sqrt(3))/(2)xxa)"units"` `=((sqrt(3))/(2)xx10)cm =(5xxsqrt(3))cm` `=(5xx1.732) cm = 8.66 cm.` | |