1.

Find the are of an equilateral triangle having each side of length 10 cm . `["Take"sqrt(3)=1.732.]`

Answer» Here ,a = 10 cm
`"(i) Area of the triangle"=((sqrt(3))/(4)xxa^(2))sq " units"`
`=((sqrt(3))/(4)xx10xx10)cm ^(2)= (25xxsqrt(3))cm^(2)`
`= (25xx1.732) cm ^(2)= 43.3 cm ^(2) `
(ii) Height of the triangle `=((sqrt(3))/(2)xxa)"units"`
`=((sqrt(3))/(2)xx10)cm =(5xxsqrt(3))cm`
`=(5xx1.732) cm = 8.66 cm.`


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