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Find the area of a parallelogram ABCD, three of whose vertices are A(0, 0), B(3, 5) and C(4, 2).

Answer» E need To find co-ordinates of DSuppose D(x, y) x+3/2 = 0+4/2x = 1y+5/2 = 0+2/2y = -3D(1, -3) AREA of PARALLELOGRAM = Area of Two TRIANGLES Area of Triangle ABC + Triangle ACD = Area of ||gm ABCD2(Area of ABC) = Area of ABCD


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