1.

Find the area of a trapezium of which the parallel sides are 102 and 60 m. the other two sides are 34 and 20 m.

Answer»

1296m²Step-by-step explanation:Use the Pythagorean THEOREM on each of the right triangles.A. H2+(42−x)2=342 and B. h2+x2=202 Solve equation B for h2 : h2=400−x2 Substitute this VALUE of h2 into equation A and expand (42−x)2 :400−x2+1764−84x+x2=1156 NOTICE that the x2 cancel out, now solve for x:2164−84x=1156 −84x=−1008 x=12m Now find the value of h: h2=400−122=256 , h=16m The formula for the area of a trapezium is: A=12h(b1+b2) Substitute the values in and simplify:A=12(16)(102+60)=8(162)=1296m²



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